Dear Uncle Colin,
Can two polynomials be equal everywhere in some non-trivial interval $[a,b]$ but not equal elsewhere?
- Lacking A Good Reasonable Answer, No Good Explanation
Hi, LAGRANGE, and thanks for your message!
The answer is “no”, but to explain why, I need to give you a few pieces of information first:
- The degree of a polynomial is the highest power of $x$ anywhere in it - so $x^6 + 1$ is a degree-six polynomial.
- A polynomial of degree $n$ or smaller has no more than $n$ zeroes (that is, there are at most $n$ places where $p(x) = 0$) unless $p(x) = 0$ everywhere.
- The difference between two polynomials, one of degree $m$ and one of degree $n$, is a polynomial degree of at most $\max(m,n)$.
So here’s the proof:
- Suppose $f(x)$ has degree $m$ and $g(x)$ has degree $n$ (without loss of generality, I’m going to assume $n>m$.)
- Consider $D(x) = f(x) - g(x)$. $D(x)$ is a polynomial of degree at most $n$.
- $D(x) = 0$ for all $x$ in the interval $[a,b]$.
- In particular, it is zero for at least $n+1$ values of $x$
- Therefore $D(x) = 0$ everywhere.
- Since $D(x) = 0$ everywhere, $f(x) = g(x)$ everywhere.
Hope that helps!
- Uncle Colin
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