# Proving three points lie on a straight line (GCSE vectors)

If you ever study GCSE vectors questions, you'll spot a pattern: there's normally a (relatively) straightforward first part which involves writing down a few vectors, and then something like "show that points $O$, $X$ and $Y$ lie on a straight line."

Pretty much every student I've ever worked with on this has asked 'how on earth do you do that?", so I thought I'd better reveal the deep, dark secret.

### It's really easy once you know how

There are two facts you need to know:

1. If vectors are multiples of each other, they're parallel;
2. If two parallel vectors start at the same point, that point and the two end points are in a straight line

That means your task is easy: you just need to show that $\vec{OX}$ and $\vec{OY}$ are parallel1.

So, in simple steps:

• Work out the vector $\vec{OX}$;
• Work out the vector $\vec{OY}$;
• Work out what you multiply $\vec{OX}$ by to get $\vec{OY}$. This may be a fraction.

Then you write down something like $\vec{OX} = \frac{3}{2}\vec{OY}$, so $OXY$ is a straight line.

It's pretty much the same trick every time - learn it, and it'll be worth about four marks to you. ## Colin

Colin is a Weymouth maths tutor, author of several Maths For Dummies books and A-level maths guides. He started Flying Colours Maths in 2008. He lives with an espresso pot and nothing to prove.

1. Your letters, of course, may differ []

### 24 comments on “Proving three points lie on a straight line (GCSE vectors)”

• ##### manisha

Your tutoring really helped me-thanks!… and my exams are almost! But, one thing I’m confused is about proving whether it is a straight line using vector method?

• ##### Colin

Thanks, Manisha – where do you get lost if you use the method in this post? (If you let me know where it gets confusing, I can try to fix it for you!)

• ##### cecilia

hi, do you have to have it so that the vector on the right side of the equal sign is the one with the nunber in front, as i did a vector question nd i didnt know whether to write 2NM = MC or NM = 1/2MC? thank you

• ##### cecilia

hi, do you have to have it so that the vector on the right side of the equal sign is the one with the nunber in front, as i did a vector question and i didnt know whether to write 2NM = MC or NM = 1/2MC? thank you

• ##### Colin

Either way is absolutely fine! I’d probably go for $2NM = MC$, myself, but that’s a point of style rather than correctness.

• ##### dina

I used to overcomplicate vector questions like these, but splitting the straight line into 2 sections with the same starting point just seems so obvious! Thank you for this method, I answered a ‘Prove..’ question correctly for the first time 🙂

• ##### Colin

ROCK ON! Really pleased to hear that 🙂

• ##### Minuka

I took the example:-
O,A and B are three points such that OA vector = a OB vector = b , mark the points C,D,E in a diagram such that OC vector = a+b , OD vector = 1/2a +b and OE=1/3b,
Given that F is the mid point of OD, Show that E,F,C lie on a straight line

If anyone do this example right they will fully understand the conditions for 3 more more vectors to lie on the same line

• ##### Tina

I’ve given the x movement and y movement of 2 of the vectors in that bracket () form and they are same. So is it one of the right methods to prove that they are in a straight line?

• ##### Colin

That should work, yes!

Dude. Dude. This is a perfect explanation of vectors. I’ve honestly been trying to find a solution to vectors that makes ACTUAL SENSE for ages. So thank you (: Very helpful

• ##### Prathibha Chandrashekar

can u please explain in geometrical method that three points lie on a same line.

• ##### Colin

What information are you given? A typical method might involve similar triangles, but without knowing what question you’re working on, I can’t really tell you!

• ##### Akhil Evilprince

I have a question:
The position vectors of A, B and C, relative to an origin are 2i+4j , 6i+8j and ki+25j , where k is positive.
Find the value of k for which ABC is a straight line.

• ##### Colin

What have you tried?

Hint: if A, B and C are in a straight line, then \vec{AB} = \lambda \vec{AC}$. • ##### Edgar Sure • ##### Louise Hudson Thankyou so much this really helped me with vectors! • ##### Sam Thanks 🙂 I finally learnt how to do this properly now! I always used to forget but now I know this: “If vectors are multiples of each other, they’re parallel;” I remember it • ##### Colin Awesome, Sam! • ##### Farha Thank you so much for such an easy explaination. Its really very helpful . • ##### Freddie I’m stuck, how do you find the vector of a kind, I haven’t been given coordinates?? just that O to A is 2a?? and O to B is 2b, how could I work this out?? • ##### Colin I’m sorry, I don’t understand your question. • ##### Mia Ford I’ve got up to 2a-b:6a-8b and I’m not sure how to see what I multiply to get the answer. Please help me • ##### Colin I would start by factorising out as much as I could: the first of those doesn’t have any non-trivial common factors, but the second is$2(3a-4b)\$.

That’s not a multiple of the first, so the two vectors you have there are not parallel.

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