Wrong, But Useful: Episode 43
podcasts/wbu43.mp3
In this month’s installment of Wrong, But Useful, our special guest cohost is @mathsjem (Jo Morgan in real life) from the indispensable resourceaholic.com.
 We start by talking about resourceaholic.com and how Jo manages to fit such a punishing blog schedule around being a nearlyfulltime maths teacher.
 Colin wonders how writing has affected Jo’s teaching practice.
 The number of the podcast is 530, an untouchable number.
 Apparently you peasants who carry money around are excited about the new £1 coin. Jo used to work at the Bank of England and has insights about how statistics can be applied to the circulation of banknotes. We refer to an article by @mscroggs about £1 coins. Dave denies ever having walked out of the Bank of England with 20 onepound coins in his shoes  but then, he would. We discuss counterfeiting.

Dave has a ridiculous thing:
Stupid question with not enough information from FB.
— Dave Gale (@reflectivemaths) April 9, 2017
Amusing about the lack of apostrophe though. #ukedchat pic.twitter.com/fMOTefywfvWe refer to my fake maths post.
 Dave’s student answered “Simplify $7a + 5b + 3a  2b$ with $10A + 3b$. Should they get the marks?

@robeastaway also has a ridiculous thing:
My 11 year old's sample SATs papers found in his book bag. "Work out 1118÷43 (no calculator)." I wish all ministers had to take these tests. pic.twitter.com/dEOiLv2fsJ
— Rob Eastaway (@robeastaway) March 22, 2017We agree that prescribing methods is wrong.
 Colin mentions @robjlow’s post on quadratics
 We discuss the effects of the new GCSE and Alevel on uptake. This involves a shoutout to @stecks and @peterrowlett’s Taking Maths Further podcast
 Last month’s puzzles: @chrishazell72 gets a gold star for a mean of 250.5 for Christian’s 1000 means puzzle, and says that getting 10 $\frac 1 3$ chances in a row over 100 trials is about 1/1000
 This month: a square has an area of 18. What’s its diagonal? Also, Find all triples of positive integers $(a,b,c)$ such that $\left(1 + \frac 1 a\right)\left(1 + \frac 1 b\right)\left(1 + \frac 1 c\right) = 2$